摘要: 原来的浪费空间 >>> a = [i for i in range (1000)]>>> a[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 2 阅读全文
posted @ 2018-02-04 14:50 andyzhang- 阅读(182) 评论(0) 推荐(0) 编辑
摘要: 现在有个需求,看列表【0,1,2,3,4,5,6,7,8,9】,要求你把列表里的每件值 加1,你怎么实现?你可能会想到2种方式 二逼表年版 a = [0,1,2,3,4,5,6,7,8,9] b = [] for i in a:b.append(i+1) a = b a [1,2,3,4,5,6,7 阅读全文
posted @ 2018-02-04 14:25 andyzhang- 阅读(315) 评论(0) 推荐(0) 编辑