摘要: 引用 int main(int argc, char const *argv[]) { int a = 10; int *p = &a; int &b = a; //int &c = 20; //错误,20无法取地址 *p = 20; cout<<a<<" "<<*p<<" "<<b<<endl; 阅读全文
posted @ 2022-08-26 16:30 言叶以上 阅读(16) 评论(0) 推荐(0) 编辑