Cannot call sendRedirect() after the response has been committed解决方法

<%		
		JudgeName judge = new JudgeName();

		request.setCharacterEncoding("utf-8");
		String name = request.getParameter("userName");
		if (name != null) {
			session.setAttribute("name", name);
			session.setMaxInactiveInterval(30);
		} else {
			response.sendRedirect("index.jsp");
			/* return; */
		}
		String pwd = request.getParameter("pwd");

		if (judge.isExists(name)) {

			if (pwd.equals("12345")) {
				response.sendRedirect("succeed.jsp");
				/*return;*/
			} else {
				session.setAttribute("msg", "密码错误");
				response.sendRedirect("failed.jsp");
				/*return;*/
			}

		} else {
			session.setAttribute("msg", "用户名不存在");
			response.sendRedirect("failed.jsp");
              /*return;*/ } %>

该页面主要实现的功能是对request的数据进行对比判断,由form表单进入该页面并不会出错,但是由于逻辑混乱导致直接进入页面时会发生两次response的重定向,所以报错

逻辑上的错误导致response可能被执行两次,两种解决方案:

1.修改逻辑

2.在response后加return;

3.但是不能再最后一个response后添加return;否则报错:

以下为修改后的代码:

<%
		JudgeName judge = new JudgeName();
		request.setCharacterEncoding("utf-8");
		String name = request.getParameter("userName");
		String pwd = request.getParameter("pwd");

		if (name != null && pwd != null) {
			session.setAttribute("name", name);
			session.setMaxInactiveInterval(30);
			
			if (judge.isExists(name)) {
				if (pwd.equals("12345")) {
					response.sendRedirect("succeed.jsp");
					
				} else {
					session.setAttribute("msg", "密码错误");
					response.sendRedirect("failed.jsp");
				}
				
			} else {
				session.setAttribute("msg", "用户名不存在");
				response.sendRedirect("failed.jsp");
			}

		} else {
			response.sendRedirect("index.jsp");
		}
	%>

 

posted @ 2018-08-17 17:34  annofyf  阅读(10385)  评论(0编辑  收藏  举报