摘要: Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest l 阅读全文
posted @ 2016-06-02 12:28 茜茜的技术空间 阅读(166) 评论(0) 推荐(0) 编辑
摘要: Sort a linked list in O(n log n) time using constant space complexity. Analysis: 1. use merge sort 2. use quick sort Java code 20160601 merge sort: 阅读全文
posted @ 2016-06-02 09:17 茜茜的技术空间 阅读(218) 评论(0) 推荐(0) 编辑
摘要: Given a list, rotate the list to the right by k places, where k is non-negative. For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3- 阅读全文
posted @ 2016-06-02 08:43 茜茜的技术空间 阅读(203) 评论(0) 推荐(0) 编辑
摘要: Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the 阅读全文
posted @ 2016-06-02 07:50 茜茜的技术空间 阅读(305) 评论(0) 推荐(0) 编辑
摘要: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解题思路: Th 阅读全文
posted @ 2016-06-02 07:32 茜茜的技术空间 阅读(148) 评论(0) 推荐(0) 编辑
摘要: Given a singly linked list L: L0→L1→…→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For 阅读全文
posted @ 2016-06-02 07:02 茜茜的技术空间 阅读(426) 评论(0) 推荐(0) 编辑
摘要: Reverse a linked list from position m to n. Do it in-place and in one-pass. For example:Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2- 阅读全文
posted @ 2016-06-02 03:15 茜茜的技术空间 阅读(244) 评论(0) 推荐(0) 编辑
摘要: Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? A linked list can be re 阅读全文
posted @ 2016-06-02 02:41 茜茜的技术空间 阅读(385) 评论(0) 推荐(0) 编辑