Leetcode Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

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解题思路： 

方法一：

 这道题主要是考虑一下最后是不是空格，方法是倒着找不是空格的字符并计数。这个速度最快。

方法二：

用split函数把字符串按照空格分隔好，返回最后那个就行。这个比较慢。

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 Java code:

Method1:

public int lengthOfLastWord(String s) {
        if(s == null || s.length() < 1) {
            return 0;
        }
        s = s.trim();
        if(s.length()==0) {
            return 0;
        }
        int result = 0;
        
        for(int i=s.length()-1; i>=0; i--) {
            if(s.charAt(i) != ' ') {
                result +=1;
            }else {
                break;
            }
        }
        return result;
    }

Method2: use split

public int lengthOfLastWord(String s) {
        if(s==null || s.length() < 1) {
            return 0;
        }
        String[] temp = s.split(" ");
        if(temp.length == 0) {
            return 0;
        }
        return temp[temp.length-1].length();
    }

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Reference:

1. http://www.cnblogs.com/springfor/p/3872326.html