Scala解析Json格式

 

Scala解析Json格式

代码块

  • Scala原生包

　　　　导入包　　　　

　　　　import scala.util.parsing.json._
 1   def main(args: Array[String]): Unit = {
 2 
 3     def regJson(json:Option[Any]) = json match {
 4       case Some(map: Map[String, Any]) => map
 5 //      case None => "erro"
 6 //      case other => "Unknow data structure : " + other
 7     }
 8     val str = "{\"host\":\"td_test\",\"ts\":1486979192345,\"device\":{\"tid\":\"a123456\",\"os\":\"android\",\"sdk\":\"1.0.3\"},\"time\":1501469230058}"
 9     val jsonS = JSON.parseFull(str)
10     val first = regJson(jsonS)
11     // 获取一级key
12     println(first.get("host"))
13     // 获取二级key
14     val dev = first.get("device")
15     println(dev)
16     val sec = regJson(dev)
17     println(sec.get("tid").toString.replace("Some(","").replace(")",""))
18   }

运行结果

Some(td_test)
Some(Map(tid -> a123456, os -> android, sdk -> 1.0.3))
a123456

 

  • GSON包

　　　　导入包　　　　

　　　　import com.google.gson.{JsonObject, JsonParser}
 1 def main(args: Array[String]): Unit = {
 2 
 3     gson("{\"host\":\"td_test\",\"ts\":1486979192345,\"device\":{\"tid\":\"a123456\",\"os\":\"android\",\"sdk\":\"1.0.3\"},\"time\":1501469230058}")
 4 
 5   }
 6 
 7   def gson(str: String) ={
 8     val json = new JsonParser()
 9     val obj = json.parse(str).asInstanceOf[JsonObject]
10     println(obj.get("device"))
11     println(obj.get("ts"))
12   }

 

运行结果：

{"tid":"a123456","os":"android","sdk":"1.0.3"}
1486979192345

posted @ 2017-08-03 11:21  anitinaj  阅读(24874)  评论(0)  编辑  收藏  举报