sql 分隔字符串
2011-03-17 11:03 calm_水手 阅读(257) 评论(0) 编辑 收藏 举报CREATE FUNCTION dbo.fnSplit(
@sInputList VARCHAR(8000), -- List of delimited items
@sDelimiter VARCHAR(8000) = ',' -- delimiter that separates items
)
RETURNS @List TABLE (item VARCHAR(8000))
BEGIN
DECLARE @sItem VARCHAR(8000)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
BEGIN
SELECT @sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
@sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))
IF LEN(@sItem) > 0 INSERT INTO @List SELECT @sItem
END
IF LEN(@sInputList) > 0 INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END
GO
--Test
--select * from fnSplit('1,2,3,4,5,6,7,8,9,0', ',')
@sInputList VARCHAR(8000), -- List of delimited items
@sDelimiter VARCHAR(8000) = ',' -- delimiter that separates items
)
RETURNS @List TABLE (item VARCHAR(8000))
BEGIN
DECLARE @sItem VARCHAR(8000)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
BEGIN
SELECT @sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
@sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))
IF LEN(@sItem) > 0 INSERT INTO @List SELECT @sItem
END
IF LEN(@sInputList) > 0 INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END
GO
--Test
--select * from fnSplit('1,2,3,4,5,6,7,8,9,0', ',')