Python装饰器限制函数运行时间超时则退出执行 函数超时停止

https://www.jb51.net/article/159375.htm


# -*- coding: utf-8 -*-
from threading import Thread
import time
class TimeoutException(Exception):
  pass
ThreadStop = Thread._Thread__stop
def timelimited(timeout):
  def decorator(function):
    def decorator2(*args,**kwargs):
      class TimeLimited(Thread):
        def __init__(self,_error= None,):
          Thread.__init__(self)
          self._error = _error
        def run(self):
          try:
            self.result = function(*args,**kwargs)
          except Exception,e:
            self._error = str(e)
        def _stop(self):
          if self.isAlive():
            ThreadStop(self)
      t = TimeLimited()
      t.start()
      t.join(timeout)
      if isinstance(t._error,TimeoutException):
        t._stop()
        raise TimeoutException('timeout for %s' % (repr(function)))
      if t.isAlive():
        t._stop()
        raise TimeoutException('timeout for %s' % (repr(function)))
      if t._error is None:
        return t.result
    return decorator2
  return decorator
@timelimited(2) # 设置运行超时时间2S
def fn_1(secs):
  time.sleep(secs)
  return 'Finished without timeout'
def do_something_after_timeout():
  print('Time out!')
if __name__ == "__main__":
  try:
    print(fn_1(3)) # 设置函数执行3S
  except TimeoutException as e:
    print(str(e))
    do_something_after_timeout()
posted @ 2020-01-10 13:55  AngDH  阅读(1430)  评论(0编辑  收藏  举报