摘要：
SELECT UserId, @i:=@i+1,gradeFROM userinfo a,(SELECT @rownum:=0) b ORDER BY grade DESC; 阅读全文
摘要：
Map<String, String> map= new HashMap<String, String>();map.put("aa", "UPDATE");map.put("bb", "INSERT");for (Object o : map.keySet()){System.out.println(o.toString() + "__" + m.get(o));} 阅读全文