浙南联合训练赛 B-Laptops
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop.
Please, check the guess of Alex. You are given descriptions of n laptops. Determine whether two described above laptops exist.
Input
The first line contains an integer n (1 ≤ n ≤ 105) — the number of laptops.
Next n lines contain two integers each, ai and bi (1 ≤ ai, bi ≤ n), where ai is the price of the i-th laptop, and bi is the number that represents the quality of the i-th laptop (the larger the number is, the higher is the quality).
All ai are distinct. All bi are distinct.
Output
If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes).
Examples
2
1 2
2 1
Happy Alex
#include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int m=1e6+10; struct node { int x,y; }a[m]; bool cmp(node a,node b) { return a.x < b.x; } int main() { int n; while(cin>>n) { for(int i=0;i<n;i++) scanf("%d %d",&a[i].x,&a[i].y); sort(a,a+n,cmp); int flag=1; for(int i=1;i<n;i++) { if(a[i].x>a[i-1].x&&a[i].y<a[i-1].y) { flag=0; cout<<"Happy Alex"<<endl; break; } } if(flag) cout<<"Poor Alex"<<endl; } }
【推荐】还在用 ECharts 开发大屏?试试这款永久免费的开源 BI 工具!
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· .NET 原生驾驭 AI 新基建实战系列:向量数据库的应用与畅想
· 从问题排查到源码分析:ActiveMQ消费端频繁日志刷屏的秘密
· 一次Java后端服务间歇性响应慢的问题排查记录
· dotnet 源代码生成器分析器入门
· ASP.NET Core 模型验证消息的本地化新姿势
· ThreeJs-16智慧城市项目(重磅以及未来发展ai)
· .NET 原生驾驭 AI 新基建实战系列(一):向量数据库的应用与畅想
· Ai满嘴顺口溜,想考研?浪费我几个小时
· Browser-use 详细介绍&使用文档
· 软件产品开发中常见的10个问题及处理方法