MDX函数使用介绍（四）：字符串函数&元组函数

        字符串函数

函数	描述
CalculationPassValue	返回在多维数据集的指定计算传递上对 MDX 表达式求得的值。
	with member measures.test as 'CalculationPassValue(membertostr([sales average])  , -1, RELATIVE)' select  {measures.test, [sales average] } on columns,   { [Time].allmembers} on rows from Sales 上面的语句按理是对的，但不能运行！待改！
CoalesceEmpty	将空单元值合并为字符串或数字。
	with member measures.test as 'CoalesceEmpty(Time.currentmember.Parent.Name, "EMPTY")' select  {measures.test  } on columns,   {time.allmembers} on rows from Sales 能运行但不是预想效果
Generate	返回通过在集合上对字符串表达式计算而创建的连锁字符串。
	看上面的
IIf	返回由逻辑测试确定的两个字符串或数值之一。
	with member measures.test as 'iif (isempty(Time.currentmember.Parent )   , "EMPTY","exist")' select  {measures.test  } on columns,   {time.allmembers} on rows from Sales
LookupCube	返回在同一数据库中另外一个指定的多维数据集上对 MDX 表达式求得的值。
	看上面的
MemberToStr	从某个成员构造一个字符串。
	with member measures.test as ' MemberToStr([store Sales]) ' select  {measures.test } on columns,   { [Time].allmembers} on rows from Sales
Name	返回维度、层次结构、级别或成员的名称。
	略
Properties	返回包含成员属性值的字符串。
	with member measures.test as 'store.currentmember.Properties("Store Manager") ' select  {measures.test } on columns,   { Descendants([Store].[All Stores].[USA],[Store].[Store Name])} on rows from Sales
SetToStr	用集合构造一个字符串。
	select  {measures.[store sales] } on columns,   { strtoset(SetToStr({[Time].[1997], [Time].[1998]}))} on rows from Sales
TupleToStr	用元组构造一个字符串。
	with member [measures].[TupleToStr] as 'TupleToStr(([Measures].[Sales Count], [Store].[All Stores].[USA])) '   SELECT  { [measures].[TupleToStr] } ON COLUMNS, [Store].allmembers ON rows from sales
UniqueName	返回维度、级别或成员的唯一名称。
	略
UserName	返回当前连接的域名和用户名。
	with member measures.test as 'username' select  { measures.test  } on columns,   {  [Time].[1997], [Time].[1998]}  on rows from Sales

 

元组函数

函数	描述
Current	返回迭代过程中集合中的当前元组。
	with set kkk as '{{[Time].[1997], [Time].[1998]}*{[Store].[All Stores].[Canada],[Store].[All Stores].[USA]} }' member measures.jjj as 'TupleToStr(kkk.current)',solve_order=1 select  { measures.[store sales],measures.jjj } on columns,   {kkk} on rows from Sales 待改！找不到current的用途！
Item	从集合中返回元组。
	with set kkk as '{{[Time].[1997], [Time].[1998]}*{[Store].[All Stores].[Canada],[Store].[All Stores].[USA]} }' member measures.jjj as 'TupleToStr(kkk.item(0).item(0))',solve_order=1 select  { measures.[store sales],measures.jjj } on columns,   {kkk} on rows from Sales
StrToTuple	用字符串构造一个元组。
	with member measures.jjj as 'StrToTuple("([store Sales], "+time.currentmember.uniquename+")")',solve_order=1 select  {  measures.jjj } on columns,   {time.allmembers} on rows from Sales