ORACLE-合并查询结果
ORACLE-合并查询结果
最近遇到了一个问题，需要将查询出来的结果中某一字段的值合并起来显示，通过自己的努力有了个Workaround，记下来以备后忘。
下面是数据库中的数据存在形式，用普通的语句查询如下
Select Iq_No,Report_No from Iq_Body
查询出的结果：
Iq_No Report_no
--------------------------------------------------
N3204101090421000002 320410109081597
N3204101090421000002 320410109081598
N3204101090421000002 320410109081599
N3204101090421000003 320410109081600
N3204101090421000003 320410109081124
--------------------------------------------------
N3204101090421000002 320410109081597
N3204101090421000002 320410109081598
N3204101090421000002 320410109081599
N3204101090421000003 320410109081600
N3204101090421000003 320410109081124
实际想要的结果：
Iq_No Report_No
--------------------------------------------
N3204101090421000002 320410109081597,320410109081598,320410109081599
N3204101090421000003 320410109081600,320410109081124
--------------------------------------------
N3204101090421000002 320410109081597,320410109081598,320410109081599
N3204101090421000003 320410109081600,320410109081124
用下面的SQL语句可以得到想要的结果：
SQL语句
1 SELECT IQ_NO,
2 REPLACE(SUBSTR(MAX(CASE
3 WHEN REPORT_NO IS NOT NULL OR LENGTH(REPORT_NO) = 0 THEN
4 SYS_CONNECT_BY_PATH(REPORT_NO, ';')
5 END),
6 2),
7 ';',
8 ',') REPORT_NO
9 FROM (SELECT IQ_NO,
10 REPORT_NO,
11 rn,
12 LEAD(rn) OVER(PARTITION BY IQ_NO ORDER BY rn) rn1
13 FROM (SELECT IQ_NO,
14 REPORT_NO,
15 ROW_NUMBER() OVER(ORDER BY REPORT_NO DESC) rn
16 FROM IQ_BODY))
17 START WITH rn1 IS NULL
18 CONNECT BY rn1 = PRIOR rn
19 GROUP BY IQ_NO
20
2 REPLACE(SUBSTR(MAX(CASE
3 WHEN REPORT_NO IS NOT NULL OR LENGTH(REPORT_NO) = 0 THEN
4 SYS_CONNECT_BY_PATH(REPORT_NO, ';')
5 END),
6 2),
7 ';',
8 ',') REPORT_NO
9 FROM (SELECT IQ_NO,
10 REPORT_NO,
11 rn,
12 LEAD(rn) OVER(PARTITION BY IQ_NO ORDER BY rn) rn1
13 FROM (SELECT IQ_NO,
14 REPORT_NO,
15 ROW_NUMBER() OVER(ORDER BY REPORT_NO DESC) rn
16 FROM IQ_BODY))
17 START WITH rn1 IS NULL
18 CONNECT BY rn1 = PRIOR rn
19 GROUP BY IQ_NO
20
