Array Partition

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

Input: [1,4,3,2]

Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4.

 

Note:

  1. n is a positive integer, which is in the range of [1, 10000].
  2. All the integers in the array will be in the range of [-10000, 10000].

 

 1 public class Solution {
 2     public int arrayPairSum(int[] nums) {
 3         Arrays.sort(nums);
 4         int result = 0, n = nums.length;
 5         for (int i = 0; i < n; i++) {
 6             if (i % 2 == 0)
 7                 result += nums[i];
 8         }
 9         return result;
10     }
11 }

 

posted @ 2017-04-28 13:44  amazingzoe  阅读(137)  评论(0编辑  收藏  举报