Diameter of Binary Tree
Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longestpath between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1 / \ 2 3 / \ 4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
Solution: Compute the left height and right height of each node, update the max diameter every time.
1 /** 2 * Definition for a binary tree node. 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 private int maxDiameter = Integer.MIN_VALUE; 12 13 public int diameterOfBinaryTree(TreeNode root) { 14 if (root == null || (root.left == null && root.right == null)) return 0; 15 16 getHeight(root); 17 return maxDiameter; 18 } 19 20 private int getHeight(TreeNode root) { 21 if (root == null) return 0; 22 if (root.left == null && root.right == null) return 1; 23 24 int leftHeight = getHeight(root.left); 25 int rightHeight = getHeight(root.right); 26 maxDiameter = Math.max(maxDiameter, leftHeight + rightHeight); 27 return 1 + Math.max(leftHeight, rightHeight); 28 } 29 }