Flip Game

You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner.

Write a function to compute all possible states of the string after one valid move.

For example, given s = "++++", after one move, it may become one of the following states:

[
  "--++",
  "+--+",
  "++--"
]

 

If there is no valid move, return an empty list [].

 

复制代码
 1 class Solution {
 2 public:
 3     vector<string> generatePossibleNextMoves(string s) {
 4         vector<string> result;
 5         if (s.size() < 2) return result;
 6         
 7         for (int i = 1; i < s.size(); i++) {
 8             if (s[i] == '+' && s[i - 1] == '+') {
 9                 s[i] = s[i - 1] = '-';
10                 result.push_back(s);
11                 s[i] = s[i - 1] = '+';
12             } 
13         }
14         return result;
15     }
16 };
复制代码

 

posted @   amazingzoe  阅读(208)  评论(0编辑  收藏  举报
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