买卖股票的最佳时机

代码：

class Solution {

public:

/**

* @param prices: Given an integer array

* @return: Maximum profit

*/

int maxProfit(vector<int> &price) {

 

int re = 0;

if(price.size()<2)

return re;

int lowest = price[0];

for(int i=1;i<price.size();i++)

{

int cur = price[i];

re = max(re,cur-lowest);

lowest = min(lowest,cur);

}

return re;

}

};

lintcode截图：