泛型类型推断

Think in java P450

public class SimplerPets {
    public static void main(String[] args) {
Map
<Person, List<? extends Pet>> petPeople = New1.map();
    //赋值没有报错
f(New1.map());//编译不通过
    //Error:(15, 18) java: 不兼容的类型: java.util.Map<java.lang.Object,java.lang.Object>无法转换为java.util.Map<com.jxufe.decorator.Person,java.util.List<? extends com.daxiyan.thinkinjava.generic.Pet>>
    f(New.<Person, List<? extends Pet>>map());

}
static void f(Map<Person, List<? extends Pet>> petPeople) {

    }
}
class New {
    public static <K,V> Map<K,V> map() {
        return new HashMap<K,V>();
    }
    public static <T> List<T> list() {
        return new ArrayList<T>();
    }
    public static <T> LinkedList<T> lList() {
        return new LinkedList<T>();
    }
    public static <T> Set<T> set() {
        return new HashSet<T>();
    }
    public static <T> Queue<T> queue() {
        return new LinkedList<T>();
    }
    // Examples:
    public static void main(String[] args) {
        Map<String, List<String>> sls = New1.map();
        List<String> ls = New1.list();
        LinkedList<String> lls = New1.lList();
        Set<String> ss = New1.set();
        Queue<String> qs = New1.queue();
    }
}

类型推断只对赋值有效,其他时候并不起作用。

posted @ 2017-10-09 16:21  Always_July  阅读(286)  评论(0编辑  收藏  举报