从字符串中分离各项

Q:现在有有一个字符串str=“//192.169.3.3:3306:user:pwd”
怎样用c++实现分离出ip，端口号，用户名，密码，注意端口号可能没有（有默认值），谁有好的办法。谢谢。

A.

(1)

#include <iostream> #include <string>

using namespace std;

int main()
{
    const string str = "//192.169.3.3:3306:user:pwd";
    string tmp;
    size_t pos = 2;
    tmp = str.substr(pos, str.find(':'));
    cout << tmp;
    ...

    return 0;
}

(2)

#include <iostream> #include <deque>
#include <vector>
using namespace std;


void parse(const char* str)
{
    char ip[32], user[32], pwd[32];
    int port = 0;
    if (sscanf(str, "//%[^:]:%d:%[^:]:%s", ip, &port, user, pwd) != 4)
     sscanf(str, "//%[^:]:%[^:]:%s", ip, user, pwd);
    printf("//%s:%d:%s:%s\n", ip, port, user, pwd);
}


int main(void)
{
    parse("//192.169.3.3:3306:user:pwd");
    parse("//192.169.3.3:user:pwd");
    return 0;
}

 

(3)

void parse(string str)
{
string ip(""),user(""),pwd("");
int port(80);
int c = count(str.begin(),str.end(),':');
str = str.substr(2);
replace(str.begin(),str.end(),':',' ');

stringstream is(str);

if(c == 2)
is>>ip>>user>>pwd;
else
if(c == 3)
is>>ip>>port>>user>>pwd;

cout < <ip < <endl;
cout < <port < <endl;
cout < <user < <endl;
cout < <pwd < <endl;

}

用stringstream也可以

 

 

(4)

#include <string.h> #include <stdio.h>

int main()
{
    char str[] = "//192.169.3.3:3306:user:pwd";
    char* p;
    p = strtok(str,":");
    while(p)
    {
        printf("%s\n",p);
        p = strtok(NULL,":");
    }
    return 0;
}