3点55再过1小时22分钟是多少呢？

方法1

include<stdio.h>

main()
{
int hour = 3;
int min = 55;

int pass_hour = 1;
int pass_min = 22;
int new_hour;
int new_min;
    new_hour = hour + pass_hour + (min + pass_min)/60;
new_min = (min + pass_min) % 60;
printf("%d:%d\n",new_hour , new_min);

}

方法2

include<stdio.h>

main()
{
int hour = 3;
int min = 55;

int pass_hour = 1;
int pass_min = 22;
int new_hour;
int new_min;
    if(min + pass_min >= 60)
{
	new_min = min + pass_min - 60;
	new_hour = hour + pass_hour + 1;
}

if(min + pass_min < 60)
{
	new_min = min + pass_min;
	new_hour = hour + pass_hour;
}

printf("%d:%d\n", new_hour , new_min);

}

方法3：（利用结构体封装）

include<stdio.h>

struct time add(struct time now, struct time pass);

struct time{
int hour;
int min;
};

main()
{
struct time now = {3, 55}, pass = {1, 33}, result;

result = add(now, pass);

printf("%d:%d\n", result.hour, result.min);

}

struct time add(struct time now, struct time pass)
{
struct time rel;
rel.hour = now.hour + pass.hour + (now.min + pass.min)/60;
rel.min = (now.min + pass.min)%60;

return rel;

}