C# 指定程序打开指定文件

            Process process = new Process();
            process.StartInfo.FileName = 指定程序exe文件路径;
            process.StartInfo.Arguments = 指定文件路径;
            process.StartInfo.UseShellExecute = false; 
            process.StartInfo.RedirectStandardOutput = false;
            process.StartInfo.RedirectStandardInput = true;
            process.StartInfo.CreateNoWindow = false;
            process.Start();
            process.WaitForExit();
            process.Close();

 

posted @ 2019-04-29 15:56  Alina_Wang  阅读(4352)  评论(0编辑  收藏  举报