Jsp万能密码漏洞修复例子

更多详细内容请查看:http://www.111cn.net/jsp/Java/58610.htm

如果网站出现这种“万能密码”漏洞该怎么办呢

'or'='or' 漏洞修复 方法有很多在这里介绍两种,咱们使用第2种

方法1: Replace过滤字符

解决方法:查找login.asp下的

 代码如下 复制代码
username=request.Form("name")

pass=request.Form("pass")
 

修改为:

 代码如下 复制代码
username=Replace(request.Form("name"), "'", "''")

pass=Replace(request.Form("pass"), "'", "''")
 

语法是屏蔽'和''字符来达到效果.


下面我把一个有万能密码的bug程序进行修改

 代码如下 复制代码
public String login()
{
  String str1 = (String)getParamenterValue("username");
  String str2 = (String)getParamenterValue("password");
  List localList = this.entityManager.findByHQL("from AdminUser where username='" + str1 + "' and password='" + str2 + "'", false, -1, -1);
  if ((localList != null) && (localList.size() > 0))
  {
    HttpSession localHttpSession = getHttpSession();
    localHttpSession.setAttribute("adminuser", localList.get(0));
    setToJsp("/managers/index.jsp");
    return " www.111cn.net ";
  }
  setToJsp("/adminlogin.jsp");
  return "toJsp";
}
 

修复之后的代码:

 代码如下 复制代码
public String login()
  {
    String str1 = (String)getParamenterValue("username");
    String str2 = (String)getParamenterValue("password");
    List localList = this.entityManager.findByHQL("from AdminUser where username='" + str1 + "' and password='" + str2 + "'", false, -1, -1);
    if ((localList != null) && (localList.size() == 1))
    {
      //if size > 1, don't login.
      AdminUser loginUser = (AdminUser)localList.get(0);
      if(loginUser.getUsername().equals(str1) && loginUser.getPassword().equals(str2)){
          HttpSession localHttpSession = getHttpSession();
          localHttpSession.setAttribute("adminuser", localList.get(0));
          setToJsp("/managers/index.jsp");
      }else{
          setToJsp("/adminlogin.jsp");
      }
      return "toJsp";
    }
    setToJsp("/adminlogin.jsp");
    return "toJsp";
  }
 

posted @ 2014-03-15 09:27  divor  阅读(1982)  评论(0编辑  收藏  举报