python遍历目录文件脚本的示例
例子
自己写的一个Python遍历文件脚本,对查到的文件进行特定的处理。没啥技术含量,但是也记录一下吧。
代码如下 复制代码
#!/usr/bin/python
# -*- coding: utf-8 -*-
import sys
import os
import shutil
dir = "/mnt/Packages"
class Packages:
def __init__(self,srcdir,desdir):
self.sdir=srcdir
self.ddir=desdir
def check(self):
print('program start...')
for dirpath
, dirnames, filenames in os.walk(self.sdir): www.111cn.Net #遍历文件
for filename in filenames:
thefile=os.path.join(dirpath,filename) #文件的绝对地址
try:
if os.path.splitext(thefile)[1]=='.rpm': #筛选.rpm格式的文件
#print('Fount rpm package: ' + thefile)
if 'inspuer' in os.popen('rpm -qpi ' + thefile).read().rstrip():
print('Found error package: ' + thefile)
shutil.copy(thefile, self.ddir) #将错误文件复制到desdir目录
f = open('list.txt', 'a') #将错误文件列表写入到list.txt
f.write(filename + ' ')
f.close()
except IOError, err:
print err
sys.exit()
if __name__ == '__main__':
dir=Packages('/mnt/cdrom','/mnt/erpm') #源目录为/mnt/cdrom,目标目录为/mnt/erpm
dir.check()
例子,遍历目录下文件
代码如下 复制代码
def search(folder, filter, allfile):
folders = os.listdir(folder)
for name in folders:
curname = os.path.join(folder, name)
isfile = os.path.isfile(curname)
if isfile:
ext = os.path.splitext(curname)[1]
count = filter.count(ext)
if count>0:
cur = myfile()
cur.name = curname
allfile.append(cur)
else:
search(curname, filter, allfile)
return allfile
例子
遍历文件夹并删除特定格式文件
代码如下 复制代码
#!/usr/bin/python
# -*- coding: utf-8 -*-
import os
def del_files(path):
for root , dirs, files in os.walk(path):
for name in files:
if name.endswith(".tmp"):
os.remove(os.path.join(root, name))
print ("Delete File: " + os.path.join(root, name))
# test
if __name__ == "__main__":
path = '/tmp'
del_files(path)