[LeetCode] 135. Candy

和 238. Product of Array Except Self 计算除自己之外的乘积很像,先左侧遍历,再右侧遍历。
Hard不过如此。

class Solution:
    def candy(self, ratings: List[int]) -> int:
        # 1
        n = len(ratings)
        if n == 1:
            return 1
        # min element is not exist
        if all(x == ratings[0] for x in ratings):
            return n
        # else
        candy = [1] * n
        for i in range(1, n):
            if ratings[i] > ratings[i - 1]:
                candy[i] = candy[i - 1] + 1
        for i in range(n - 2, -1, -1):
            if ratings[i] > ratings[i + 1] and candy[i] <= candy[i + 1]:
                candy[i] = candy[i + 1] + 1
        return sum(candy)

image

posted @ 2024-07-09 00:35  夜歌乘年少  阅读(1)  评论(0编辑  收藏  举报