分布式进程

# taskmanager.py
# -*- coding: utf-8 -*-
import queue
import random
from multiprocessing.managers import BaseManager

# 发送任务的队列:
task_queue = queue.Queue()
# 接收结果的队列:
result_queue = queue.Queue()


def return_task_queue():
global task_queue
return task_queue


def return_result_queue():
global result_queue
return result_queue


class QueueManager(BaseManager):
pass


if __name__ == '__main__':
# 把两个Queue都注册到网络上, callable参数关联了Queue对象:
# pickle模块不能序列化lambda function,故我们需要自行定义函数,实现序列化,代码修改如下:
QueueManager.register('get_task_queue', callable=return_task_queue)
QueueManager.register('get_result_queue', callable=return_result_queue)
# 绑定端口5000, 设置验证码'abc':
manager = QueueManager(address=('127.0.0.1', 5000), authkey=b'abc')
# 启动Queue:
manager.start()
# 获得通过网络访问的Queue对象:
task = manager.get_task_queue()
result = manager.get_result_queue()
# 放几个任务进去:
for i in range(10):
n = random.randint(0, 10000)
print('Put task %d...' % n)
task.put(n)
# 从result队列读取结果:
print('Try get results...')
for i in range(10):
r = result.get(timeout=10)
print('Result: %s' % r)
# 关闭:
manager.shutdown()

manager.shutdown()
print('master exit.')

 

# taskworker.py
# -*- coding: utf-8 -*-
import time, sys, Queue
from multiprocessing.managers import BaseManager

# 创建类似的QueueManager:
class QueueManager(BaseManager):
pass

# 由于这个QueueManager只从网络上获取Queue,所以注册时只提供名字:
QueueManager.register('get_task_queue')
QueueManager.register('get_result_queue')

# 连接到服务器,也就是运行taskmanager.py的机器:
server_addr = '127.0.0.1'
print('Connect to server %s...' % server_addr)
# 端口和验证码注意保持与taskmanager.py设置的完全一致:
m = QueueManager(address=(server_addr, 5000), authkey='abc')
# 从网络连接:
m.connect()
# 获取Queue的对象:
task = m.get_task_queue()
result = m.get_result_queue()
# 从task队列取任务,并把结果写入result队列:
for i in range(10):
try:
n = task.get(timeout=1)
print('run task %d * %d...' % (n, n))
r = '%d * %d = %d' % (n, n, n*n)
time.sleep(1)
result.put(r)
except Queue.Empty:
print('task queue is empty.')
# 处理结束:
print('worker exit.')
 


参考 :https://www.liaoxuefeng.com/wiki/001374738125095c955c1e6d8bb493182103fac9270762a000/001386832973658c780d8bfa4c6406f83b2b3097aed5df6000

https://blog.csdn.net/tpc4289/article/details/79280659/

posted @ 2019-01-09 16:39  alex_python  阅读(240)  评论(0编辑  收藏  举报