玄学快读

不保证正确性

class IO {
	private:
		// 缓冲大小 
		static const int BUF = 128 * 1024;
		// 输入输出流 
		FILE *in, *out;
		char rbuf[BUF], wbuf[BUF], *rs, *rt;
		int pos;
		// EOF 
		bool eof;
	public:
		// fread 和 fwrite 
		bool load() { return (rt = (rs = rbuf) + fread(rbuf, 1, BUF, in)) == rs;}
		void flush() { fwrite(wbuf, 1, pos, out); pos = 0;}
		
		// 构造和析构 
		IO() { in = stdin, out = stdout, rs = rt = rbuf, pos = 0, eof = 0;}
		~IO() { flush();}
		
		// 文件 
		void open_r(const void* ch) { in = fopen((char*)ch, "r");}
		void open_w(const void* ch) { out = fopen((char*)ch, "w");}
		void open_r(FILE* p) { in = p;}
		void open_w(FILE* p) { out = p;}
		IO(const void* ch) { in = fopen((char*)ch, "r"), out = stdout, rs = rt = rbuf, pos = 0, eof = 0;}
		IO(FILE* p) { in = p, out = stdout, rs = rt = rbuf, pos = 0, eof = 0;}
		bool end() { return eof;}
		
		// 基础操作 
		inline void pc(const char c) { if(pos >= BUF) flush(); wbuf[pos ++] = c;}
		inline char gc() { if(rs == rt) eof = load(); return eof ? EOF : *rs ++;}
		
		// 读入 
		template<typename T>
		inline IO& operator >> (T &x) {
			register char c, f = 1;
			while(c = gc(), c < '0' || c > '9') if(c == '-') f = ! f;
			x = c ^ 48;
			while(c = gc(), c >= '0' && c <= '9' && !eof) x = (x << 3) + (x << 1) + (c ^ 48);
			return (x = f ? x : -x), *this;
		}
		inline IO& operator >> (char &c) { return c = gc(), *this;}
		inline IO& operator >> (char* c) {
			while(*c = gc(), *c == '\n' || *c == '\r' || *c == ' ' || *c == '\t');
			while(*++ c = gc(), *c != '\n' && *c != '\r' && *c != ' ' && *c != '\t' && ! eof);
			return (*c = '\0'), *this;
		}
		inline IO& getline(char* c)
		{ while(*c = gc(), *c != '\n' && *c != '\r' && ! eof) ++ c; *c = '\0'; return *this;}
		inline IO& operator >> (string &s) {
			register char c;
			while(c = gc(), c == '\n' || c == '\r' || c == ' ' || c == '\t');
			s = c;
			while(c = gc(), c != '\n' && c != '\r' && c != ' ' && c != '\t') s += c;
			return *this;
		}
		inline IO& operator >> (long double &x) {
			register char c, op = 1; long double e = 1;
			while(c = gc(), ! isdigit(c)) if(c == '-') op = ! op;
			x = c ^ 48;
			while(c = gc(), isdigit(c)) x = (x * 10) + (c ^ 48);
			if(c == '.') while(e /= 10, c = gc(), isdigit(c)) x += (c ^ 48) * e;
			return (x = op ? x : -x), *this;
		}
		inline IO& operator >> (double &x) {
			long double y; *this >> y; return x = y, *this;
		}
		
		// 输出
		template<typename T>
		inline IO& operator << (T x) {
			if(x < 0) pc('-'), x = -x;
			register T y = 10;
			while(y <= x) y = (y << 3) + (y << 1);
			while(y /= 10) pc((x / y) ^ 48), x %= y;
			return *this;
		}
		inline IO& operator << (const char c) { return pc(c), *this;}
		inline IO& operator << (const char* c) { while(*c) pc(*c ++); return *this;}
		//inline IO& operator << (char c) { return pc(c), *this;}
		inline IO& operator << (char* c) { while(*c) pc(*c ++); return *this;}
		inline IO& putline(char* c) { while(*c) pc(*c ++); return pc('\n'), *this;}
		inline IO& operator << (string s) { return *this << s.c_str();}
		template<typename T>
		inline void print(T x, short y) {
			T t; *this << (int)(t = floor(x));
			if(! y) return;
			pc('.');
			while(y) { x -= t, x *= 10; *this << (int)floor(x); y --;}
		}
};
posted @ 2019-01-11 15:27  akakw1  阅读(237)  评论(0编辑  收藏  举报