ajax 获取服务器返回的XML字符串

前台

解析失败不会抛出任何异常, 只会返回一个给定的错误文档

   let l = console.log
let http = ajanuw.create({
      uri: 'http://localhost:1995/api',
      timeout: 3000
    });

    http.request('get', '/xml', {
        name: 'xml',
        query: {
          data: 1
        },
        resType: 'text'
      })
      .then(res => {
        let data = res.data

        // l(data)
        // let dataview = new DataView(data)
        // var ints = new Int32Array(data.byteLength / 4);
        // for (var i = 0; i < ints.length; i++) {
        //   ints[i] = dataview.getInt32(i * 4);
        // }

        var parser = new DOMParser();
        var doc = parser.parseFromString(data, 'application/xml');
        l(doc)
      })

 http.request('get', '/xml', {
        name: 'xml',
        query: {
          data: 1
        },
        resType: 'document'
      })
      .then(res => {
        let data = res.data
        l(data)
      })

后台

  @Get('xml')
  @Header('access-control-allow-origiN', '*')
  xml(@Query() query): Observable < string > {
    l(query)
    let data = bindNodeCallback(fs.readFile)(path.resolve(__dirname, './', 'test.xml')).pipe(map(v => v.toString('utf8')))
    return data
  }
posted @ 2018-06-28 10:07  Ajanuw  阅读(919)  评论(0编辑  收藏  举报