rxjs 常用的静态操作符

Observable

import { Observable } from "rxjs";

const l = console.log;

// 创建 Observable
var observable = new Observable((subscribe) => {
  var id = setInterval(() => {
    subscribe.next(123);
    subscribe.error("err: ...");
    subscribe.complete();
  }, 1000);

  // 提供取消和清理 interval 资源的方法
  return function unsubscribe() {
    clearInterval(id);
  };
});

// 订阅 Observable
var sub = observable.subscribe({ next: l, error: l, complete: l });

// .add() 合并多个订阅,以便同时取消订阅
// sub.add(childSubscription);

// 撤销 add的合并
// sub.remove(childSubscription);

// 3s后取消订阅
setTimeout(() => {
  sub.unsubscribe();
}, 3000);

of(...items)from([...items])

按顺序发出每个元素, from 可以代替 fromPromise

import { of, from } from "rxjs";

of(1, 2, 3).subscribe(l); // 1,2,3

from([1, 2, 3]).subscribe(l); // 1,2,3
from( Promise.resolve(1) ).subscribe(l);  // 1
from( Promise.resolve([1]) ).subscribe(l); // [1]

bindCallback

把普通的回调函数转化为 Observable

import { bindCallback } from "rxjs";

const test = (cb) => cb(1);
let o$ = bindCallback(test)();
o$.subscribe((v) => l(v)); // 1

bindNodeCallback

把标准的node回调函数转化为 Observable

let { bindNodeCallback } = require("rxjs");
let fs = require("fs");
// fs.readFile("./test.jss", "utf8", (e, d) => (!!e ? l(e) : l(d)));

let o$ = bindNodeCallback(fs.readFile)("./test.jss", "utf8");
o$.subscribe(v => l(v), e => l(e));

combineLatest

组合多个流以创建一个流, 其值是根据每个输入流的最新值计算 (如果你要合并多个Subject就用这个)

import { combineLatest, of, timer } from "rxjs";
let o1$ = of(233);
let o2$ = of(12);
let o3$ = timer(0, 1000);

combineLatest([o1$, o2$, o3$]).subscribe(l);

// [ 233, 12, 0 ]
// [ 233, 12, 1 ]
// [ 233, 12, 2 ]
// ...

EMPTY

仅仅发出 complete 通知,其他什么也不做

let { EMPTY } = require("rxjs");
EMPTY.subscribe(l, l, () => l("done")); // done

forkJoin

连接传递的Observables发出的最后一个值。

let { forkJoin, of } = require("rxjs");
forkJoin(of(1), of(2, 3)).subscribe(l); // [ 1, 3 ]

merge

把多个流的合并到一个 流, 按顺序执行,异步流会被延后

import { merge, of, from } from "rxjs";
merge(of(1), of(4), from(["a", "b"])).subscribe(l); // 1 4 a b

concat

它顺序地从给定的Observable中发出所有值,必须等上一个完成才执行下一个

let { concat, interval, of } = require("rxjs");
let { take } = require("rxjs/operators");

let o1$ = interval(1000).pipe(take(4)); // take 接收源 最初的N个值
let o2$ = of(233);

concat(o1$, o2$).subscribe(l); // 0,1,2,3,233

never

创建一个不向观察者发出任何项的 Observable

let { never } = require("rxjs");
never().subscribe(l, l, () => l("done")); // 

range

发出指定范围内的数字序列

import { range, toArray } from "rxjs";
range(1,4).pipe( toArray() ).subscribe(l) // [ 1, 2, 3, 4 ]

throwError

仅仅发出 error 通知

import { throwError } from "rxjs";
throwError( () => new Error("err message") ).subscribe({ error: l }); // err message

timer

import { timer, interval } from "rxjs";

// 延迟3秒发送第一个值,然后马上结束
timer(3000).subscribe(l) // 0
  
//每隔3s发送一个值,第一个值延迟5s
timer(5000, 3000).subscribe(l)

timer(0, 1000).subscribe(n => console.log('timer', n));
interval(1000).subscribe(n => console.log('interval', n));

interval

在指定的时间间隔内发出序列号 0+

let { interval } = require("rxjs");
let { take } = require("rxjs/operators");
interval(200).pipe( take(3) ).subscribe(l); // 0,1,2

defer

懒惰地创建Observable (订阅时创建)

let { defer, of } = require("rxjs");
let o$ = defer(() => Math.random() > 0.5 ? of(1) : of(2) );
o$.subscribe(l);

zip

其值根据其每个输入Observable的值按顺序计算

let { zip, of } = require("rxjs");
let { map } = require("rxjs/operators");

let age$ = of(27, 25, 29);
let name$ = of("Foo", "Bar", "Beer");
let isDev$ = of(true, true, false);

zip(age$, name$, isDev$)
  .pipe(map(([age, name, isdev]) => ({ age, name, isdev })))
  .subscribe(l);

// res
{ age: 27, name: 'Foo', isdev: true }
{ age: 25, name: 'Bar', isdev: true }
{ age: 29, name: 'Beer', isdev: false }

iif

在订阅时检查布尔值,并在两个可观察源之一之间进行选择

import { iif, of } from "rxjs";
iif(() => Math.random() > 0.5, of("then"), of("else")).subscribe(l); // then | else

fromEvent

给定事件触发时响应

import { fromEvent } from "rxjs";
const clicks$ = fromEvent(document, 'click');
clicks$.subscribe(l);

onErrorResumeNext

将无错误地移动到下一个源

let { onErrorResumeNext, of } = require("rxjs");
let { map } = require("rxjs/operators");

onErrorResumeNext(
  of(1, 2, 0, 1).pipe(
    map(el => {
      if (el === 0) throw Error("000");
      return el + el;
    }),
  ),
  of("2"),
).subscribe(l, err => console.error(err), () => l("done")); // 2, 4, 2, done

pairs

将对象转换为Observable

let { pairs, of } = require("rxjs");
pairs({
  name: "ajanuw",
  age: 14,
}).subscribe(l); // [ 'name', 'ajanuw' ] [ 'age', 14 ]

partition

将源 Observable 拆分为两个,一个具有满足谓词的值,另一个具有不满足谓词的值

import { partition, from, toArray } from "rxjs";

const [needs$, nneeds$] = partition(from([2, 3, 4]), (i) => i <= 3);
needs$.pipe( toArray() ).subscribe(l)  // [ 2, 3 ]
nneeds$.pipe( toArray() ).subscribe(l) // [ 4 ]

race

返回,第一个Observable的反映的输出,然后结束

let { race, of, interval } = require("rxjs");
race(interval(1000), of(2, 22), of(3)).subscribe(l); // 2 22
posted @ 2018-04-09 10:36  Ajanuw  阅读(1020)  评论(0编辑  收藏  举报