一、错误代码:
public int findLast (int[] x, int y)
{
//Effects: If x==null throw NullPointerException
// else return the index of the last element
// in x that equals y.
// If no such element exists, return -1
for (int i=x.length-1; i > 0; i--)
{
if (x[i] == y)
{
return i;
}
}
return -1;
}
// test: x=[2, 3, 5]; y = 2
// Expected = 0
回答:
1.检测不到x[0]
2.令x = NULL
3.x = [2,3]; y = 3
4.x = [2,3]; y = 1
二、错误代码
public static int lastZero (int[] x)
{
//Effects: if x==null throw NullPointerException
// else return the index of the LAST 0 in x.
// Return -1 if 0 does not occur in x
for (int i = 0; i < x.length; i++)
{
if (x[i] == 0)
{
return i;
}
}
return -1;
}
// test: x=[0, 1, 0]
// Expected = 2
回答:
1.要求返回最后一个零的位置,代码返回第一个零的位置
2.x = NULL;
3.x = [1,0];
4.x = [0,1];