java网页程序采用 spring 防止 csrf 攻击 转

银行项目开发过程中,基本都会采用 spring 框架,所以完全可以不用自己开发 filter 去拦截 csrf 攻击的请求,而直接采用实现 spring 提供的 HandlerInterceptor 来实现。 从本质上来说,这也是一个 filter.  我这里就直接实现它来 防止 csrf 攻击.

基本思路:
1. 用户登录之后,后台程序生产一个 csrftoken 的 token ,放在 cookies 中,并且记录在 session 中。
2. 当客户端发出请求的访问后台程序的时候,经过自己实现的HandlerInterceptor 来拦截.
3. 拦截的基本方法是检查请求的参数中是否有csrftoken ,并检查这个值,是否合法有效(不为空,并且得到的参数等于cookies 中保存的值,而且还要等于session 中的值,那么就是合法的)

 

package com.yihaomen.intercepter;

import javax.servlet.http.Cookie;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.web.servlet.HandlerInterceptor;
import org.springframework.web.servlet.ModelAndView;

public class CsrfIntercepter implements HandlerInterceptor {     

public  static final String CSRFNUMBER = "csrftoken";
    public boolean preHandle(HttpServletRequest request,HttpServletResponse response, Object handler) throws Exception {
    
        String keyFromRequestParam = (String) request.getParameter(CSRFNUMBER);
        String keyFromCookies="";
        boolean result=false;
        Cookie[] cookies = request.getCookies();
        if(cookies!=null){
            for (int i = 0; i < cookies.length; i++) {    
                String name = cookies[i].getName();
                if(CSRFNUMBER.equals(name) ) {    
                    keyFromCookies= cookies[i].getValue();    
                }    
            }
        }
    
        if((keyFromRequestParam!=null && keyFromRequestParam.length()>0 &&
                keyFromRequestParam.equals(keyFromCookies) &&
                keyFromRequestParam.equals((String)request.getSession().getAttribute(CSRFNUMBER)))) {
            result=true;
        }else{
            request.getRequestDispatcher("/error/400").forward(request, response);
        }
        
        return result;
    }
    
    public void afterCompletion(HttpServletRequest arg0, HttpServletResponse arg1,
            Object arg2, Exception arg3) throws Exception {
        
    }
    
    public void postHandle(HttpServletRequest arg0, HttpServletResponse arg1,
            Object arg2, ModelAndView arg3) throws Exception {
        
    }
}

posted on 2017-12-04 10:26  为莹  阅读(2276)  评论(0编辑  收藏  举报