压测RabbitMQ消费能力

最近运维反馈线上监控到消费RabbitMQ消息队列过慢，目前只有20左右，监控平台会有消息积压的告警。

开发修改了一版应用服务的版本，提交给我做压测验证。

之前没有做过消息中间件的压测，网上找了一圈测试方法，并且和开发沟通，最终确认通过压测RabbitMQ event消息处理的接口来完成本次的压测验证。

压测脚本：

import pika
import multiprocessing as mp
import time


def main(counter):
    routing_key = "busi.mc.event.XXXX"                          # 被压测的应用服务的key，指定消息的消费者
    credentials = pika.PlainCredentials('guest', 'guest')
    parameters = pika.ConnectionParameters('XXX.XX.XXX.XX',
                                   5672,
                                   '/',
                                   credentials)

    connection = pika.BlockingConnection(parameters)                                         # 连接 RabbitMQ
    channel = connection.channel()                                                           # 创建频道

    for i in range(1, counter):                                                              # 循环生产信息，供消费者（被压测的应用服务）消费
        channel.basic_publish(exchange='mc-direct-exchange', routing_key=routing_key,
                      body='{"clientId":"5e8J8aoi4F380gpDS4sdfd","eventType":1}',
                      properties=pika.BasicProperties(
                          content_type="text/plain",
                          delivery_mode=1))
        time.sleep(0.1)
        # if counter % 600 == 0:
        #     time.sleep(1)
    
    connection.close()                        # 关闭连接

def loop_test(counter):
    for i in range(1, counter):
        main()
        if counter % 100 == 0:
            time.sleep(1)                     # 单个频率  


if __name__ == "__main__":
    # Define an output queue
    output = mp.Queue()

    # Setup a list of processes that we want to run
    processes = [mp.Process(target=main, args=(100000,)) for x in range(20)]    # 消息总条数   并发数

    # Run processes
    for p in processes:
        p.start()

    # Exit the completed processes
    for p in processes:
        p.join()

    # Get process results from the output queue
    # results = [output.get() for p in processes]

    # print(results)