摘要: #include<stdlib.h>#include<stdio.h>#include<string.h>intmain(intargc,char*argv[]){intnum=0;if(argc!=2){printf("usage:%sn\n",argv[0]);return0;}num=atoi(argv[1]);printf("Error#%d:%s\n",num,strerror(num));return0;} 阅读全文
posted @ 2012-08-09 15:43 ahuo 阅读(194) 评论(0) 推荐(0) 编辑