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asp.net:

cs代码:
            TextBox1.Attributes.Add("onkeydown", "SubmitKey('Button1');");
            TextBox2.Attributes.Add("onkeydown", "SubmitKey('Button1');");

js代码:
<script type="text/javascript">
    function SubmitKey(button)
    {   
      if (event.keyCode == 13)
      {       
            event.returnValue = false;
            document.all[button].click();
      }
}
</script>
TextBox1和TextBox2对应用户名和密码框!!
Button1对应是提交按钮!!

 

 

 

winform:

 private void txtUserPassword_KeyDown(object sender, KeyEventArgs e)
        {
            if (e.KeyCode == Keys.Enter)
            {
                btnOK_Click(sender, e);
            }
            else
            {
                return;
            }
        }

posted @ 2009-02-21 11:44  小师傅  阅读(408)  评论(0编辑  收藏  举报