dbt

Procedure Relocate(s : state; b : base_index)
{ Move base for state s to a new place beginning at b }
begin
    foreach input character c for the state s
    { i.e. foreach c such that check[base[s] + c]] = s }
    begin
        check[b + c] := s;     { mark owner }
        base[b + c] := base[base[s] + c];     { copy data }
        { the node base[s] + c is to be moved to b + c;
          Hence, for any i for which check[i] = base[s] + c, update check[i] to b + c }
        foreach input character d for the node base[s] + c
        begin
            check[base[base[s] + c] + d] := b + c
        end;
        check[base[s] + c] := none     { free the cell }
    end;
    base[s] := b
end
Definition 2. For a transition from state s to t which takes character c as the input, the condition maintained in the double-array trie is:

check[base[s] + c] = s
base[s] + c = t

sDouble-Array Relocation

根据定义2,base[s] + c = t;

而 s, base[s], t, base[t], base[b+c] ,u,b 均为 数组下标,c,d为字符序列码,即偏移量。

base[s]只是一个基地址,与数组中该下标对应的base,check是否为空,无关。

base[s] = k

base[s] + c = t;  b + c = t',  base[b+c] = base[t'];  因此: 

check[b + c] := s; { mark owner }

base[b + c] := base[base[s] + c]; { copy data }

可以理解为: check[t'] = s = check[t]; base[t'] = base[t]; 即将 t(base[s] + c) 结点的base,check 值复制到 t'结点中。

再调整t结点的孩子结点的check值,使其指向新的父节点t'。

check[i] = base[s] + c 即 check[i] = t; 

u = base[t] + d = base[base[s] + c] + d ; check[u] = check[base[base[s]+c] + d];

check[u] = t 即是:  

check[base[base[s]+c] + d] = base[s] + c = t

修改父节点后:

check[base[base[s]+c] + d] = b+c = t'

释放原先的t结点

check[base[s] + c] := none 即是 check[t] := none

令s指向新的孩子结点:

base[s] = b;



 

 

posted on 2014-03-30 15:46  agilezing  阅读(335)  评论(0编辑  收藏  举报

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