摘要:
数组void build(char *s){ int rt=0; for(int i=0;s[i];i++) { int x=s[i]-'a'; if(... 阅读全文
摘要:
What Are You Talking AboutTime Limit: 10000/5000 MS (Java/Others) Memory Limit: 102400/204800 K (Java/Others)Total Submission(s): 2... 阅读全文
摘要:
What Are You Talking AboutTime Limit: 10000/5000 MS (Java/Others) Memory Limit: 102400/204800 K (Java/Others)Total Submission(s): 2... 阅读全文