iOS - 地图坐标纠偏
2017-08-02 09:14 菜鸟Alex 阅读(403) 评论(0) 编辑 收藏 举报-
对于服务器返回的坐标进行纠偏 纠偏后展示到系统自带地图上
-
WGS84TOGCJ02.h文件
-
导入必要的框架
#import <Foundation/Foundation.h>
#import <CoreLocation/CoreLocation.h>
@interface WGS84TOGCJ02 : NSObject
//判断是否已经超出中国范围
+(BOOL)isLocationOutOfChina:(CLLocationCoordinate2D)coordinate;
//转GCJ-02
+(CLLocationCoordinate2D)transformFromWGSToGCJ:(CLLocationCoordinate2D)wgsCoordinate;
@end
- WGS84TOGCJ02.m中实现方法
#import "WGS84TOGCJ02.h"
const double a = 6378245.0;
const double ee = 0.00669342162296594323;
const double pi = 3.14159265358979324;
@implementation WGS84TOGCJ02
+(CLLocationCoordinate2D)transformFromWGSToGCJ:(CLLocationCoordinate2D)wgsCoordinate
{
CLLocationCoordinate2D adjustLoc;
if([self isLocationOutOfChina:wgsCoordinate]){
adjustLoc = wgsCoordinate;
}else{
double adjustLat = [self transformLatWithX:wgsCoordinate.longitude - 105.0 withY:wgsCoordinate.latitude - 35.0];
double adjustLon = [self transformLonWithX:wgsCoordinate.longitude - 105.0 withY:wgsCoordinate.latitude - 35.0];
double radLat = wgsCoordinate.latitude / 180.0 * pi;
double magic = sin(radLat);
magic = 1 - ee * magic * magic;
double sqrtMagic = sqrt(magic);
adjustLat = (adjustLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
adjustLon = (adjustLon * 180.0) / (a / sqrtMagic * cos(radLat) * pi);
adjustLoc.latitude = wgsCoordinate.latitude + adjustLat;
adjustLoc.longitude = wgsCoordinate.longitude + adjustLon;
}
return adjustLoc;
}
//判断是不是在中国
+(BOOL)isLocationOutOfChina:(CLLocationCoordinate2D)coordinate
{
if (coordinate.longitude < 72.004 || coordinate.longitude > 137.8347 || coordinate.latitude < 0.8293 || coordinate.latitude > 55.8271)
return YES;
return NO;
}
+(double)transformLatWithX:(double)x withY:(double)y
{
double lat = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * sqrt(fabs(x));
lat += (20.0 * sin(6.0 * x * pi) + 20.0 *sin(2.0 * x * pi)) * 2.0 / 3.0;
lat += (20.0 * sin(y * pi) + 40.0 * sin(y / 3.0 * pi)) * 2.0 / 3.0;
lat += (160.0 * sin(y / 12.0 * pi) + 320 * sin(y * pi / 30.0)) * 2.0 / 3.0;
return lat;
}
+(double)transformLonWithX:(double)x withY:(double)y
{
double lon = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * sqrt(fabs(x));
lon += (20.0 * sin(6.0 * x * pi) + 20.0 * sin(2.0 * x * pi)) * 2.0 / 3.0;
lon += (20.0 * sin(x * pi) + 40.0 * sin(x / 3.0 * pi)) * 2.0 / 3.0;
lon += (150.0 * sin(x / 12.0 * pi) + 300.0 * sin(x / 30.0 * pi)) * 2.0 / 3.0;
return lon;
}
@end