摘要: Given a prime p (p<108),you are to find min{x2+y2},where x and y belongs to positive integer, so that x2+y2=0 (mod p).打表可以看出结论: x=4k+3则没有平方和会等于P 阅读全文
posted @ 2014-05-25 22:15 acvc 阅读(191) 评论(0) 推荐(0) 编辑