438D - The Child and Sequence

D. The Child and Sequence

time limit per test

4 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

At the children's day, the child came to Picks's house, and messed his house up. Picks was angry at him. A lot of important things were lost, in particular the favorite sequence of Picks.

Fortunately, Picks remembers how to repair the sequence. Initially he should create an integer array a[1], a[2], ..., a[n]. Then he should perform a sequence of m operations. An operation can be one of the following:

1. Print operation l, r. Picks should write down the value of .
2. Modulo operation l, r, x. Picks should perform assignment a[i] = a[i] mod x for each i (l ≤ i ≤ r).
3. Set operation k, x. Picks should set the value of a[k] to x (in other words perform an assignment a[k] = x).

Can you help Picks to perform the whole sequence of operations?

Input

The first line of input contains two integer: n, m (1 ≤ n, m ≤ 105). The second line contains n integers, separated by space:a[1], a[2], ..., a[n] (1 ≤ a[i] ≤ 109) — initial value of array elements.

Each of the next m lines begins with a number type .

• If type = 1, there will be two integers more in the line: l, r (1 ≤ l ≤ r ≤ n), which correspond the operation 1.
• If type = 2, there will be three integers more in the line: l, r, x (1 ≤ l ≤ r ≤ n; 1 ≤ x ≤ 109), which correspond the operation 2.
• If type = 3, there will be two integers more in the line: k, x (1 ≤ k ≤ n; 1 ≤ x ≤ 109), which correspond the operation 3.

Output

For each operation 1, please print a line containing the answer. Notice that the answer may exceed the 32-bit integer.

这题关键是证明啊。   好线段树。

详细证明见：http://codeforces.com/blog/entry/12513 

 

#include <bits/stdc++.h>
using namespace std;
const int MAX = 1e5+10;
typedef long long LL;
LL sum[MAX<<2],Max[MAX<<2];
void push_up(int o) {
    sum[o]=sum[o<<1]+sum[o<<1|1];
    Max[o]=max(Max[o<<1],Max[o<<1|1]);
}
void build(int L,int R,int o) {
    if(L==R) {
        scanf("%I64d",&Max[o]);
        sum[o]=Max[o]; return ;
    }
    int mid=(L+R)>>1;
    build(L,mid,o<<1);
    build(mid+1,R,o<<1|1);
    push_up(o);
}
void modify1(int L,int R,int o,int ls,int rs,int mod) {
    if(L==R) {
        sum[o]=Max[o]=sum[o]%mod; return;
    }
    if(Max[o]<mod) return ;
    int mid=(L+R)>>1;
    if(ls<=mid) modify1(L,mid,o<<1,ls,rs,mod);
    if(rs>mid) modify1(mid+1,R,o<<1|1,ls,rs,mod);
    push_up(o);
}
void modify2(int L,int R,int o,int k,int x) {
    if(L==R) {
        sum[o]=Max[o]=x; return ;
    }
    int mid=(L+R)>>1;
    if(k<=mid) modify2(L,mid,o<<1,k,x);
    else modify2(mid+1,R,o<<1|1,k,x);
    push_up(o);
}
LL Query(int L,int R,int o,int ls,int rs) {
    if(ls<=L&&rs>=R) {
        return sum[o];
    }
    LL res=0;
    int mid=(L+R)>>1;
    if(ls<=mid) res+=Query(L,mid,o<<1,ls,rs);
    if(rs>mid) res+=Query(mid+1,R,o<<1|1,ls,rs);
    return res;
}
int main() {
    int n,m; int t,l,r,k,x;
    while(scanf("%d %d",&n,&m)==2) {
        build(1,n,1);
        for(int i=0;i<m;i++) {
            scanf("%d",&t);
            if(t==1) {
                scanf("%d %d",&l,&r) ;
                printf("%I64d\n",Query(1,n,1,l,r));
            }
            else if(t==2) {
                scanf("%d %d %d",&l,&r,&x);
                modify1(1,n,1,l,r,x) ;
            }
            else {
                scanf("%d %d",&k,&x);
                modify2(1,n,1,k,x);
            }
        }
    }
    return 0;
}