摘要: 2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.What is the smallest positive number that isevenly divisibleby all of the numbers from 1 to 20?#include #include #include #include #define N 20 int gcd(int a, int b){ if(b==0) return a; ... 阅读全文
posted @ 2014-02-11 14:58 acutus 阅读(116) 评论(0) 推荐(0) 编辑
摘要: A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 9199.Find the largest palindrome made from the product of two 3-digit numbers.#include#include#include#include#include#includebool palindromic(int n) //判断一个整数是否为回文数{ char ... 阅读全文
posted @ 2014-02-11 14:41 acutus 阅读(185) 评论(0) 推荐(0) 编辑
摘要: The prime factors of 13195 are 5, 7, 13 and 29.What is the largest prime factor of the number 600851475143 ?#include#include#include#include#include#include#define N 600851475143bool prim(int n){ int i; for(i=2; i*i<=n; i++) { if(n%i==0) return false; } return true;}... 阅读全文
posted @ 2014-02-11 14:30 acutus 阅读(138) 评论(0) 推荐(0) 编辑
摘要: Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be:1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of the even-value 阅读全文
posted @ 2014-02-11 14:13 acutus 阅读(175) 评论(0) 推荐(0) 编辑
摘要: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.Find the sum of all the multiples of 3 or 5 below 1000.题目大意:10以下的自然数中,属于3和5的倍数的有3,5,6和9,它们之和是23.找出1000以下的自然数中,属于3和5的倍数的数字之和。#include #include #include void solve(){ in... 阅读全文
posted @ 2014-02-11 13:47 acutus 阅读(150) 评论(0) 推荐(0) 编辑
摘要: While preparing this problem set the jury has run into the following problem: it was necessary to send by e-mail the texts of the problems. As it is well known, e-mail is not reliable, messages are sent not enciphered, there is a danger that someone can intercept them. The members of the program com 阅读全文
posted @ 2014-01-16 10:56 acutus 阅读(392) 评论(0) 推荐(0) 编辑
摘要: You programmers are lucky! You don't have to deal with these terrible people – designers… This story happened with me not so long ago. We had an order from a company building a new hotel. One day they brought a sketch to our workshop. They said that THIS was invented by a very cool designer. The 阅读全文
posted @ 2014-01-16 01:14 acutus 阅读(250) 评论(0) 推荐(0) 编辑
摘要: LetAn= sin(1–sin(2+sin(3–sin(4+…sin(n))…)LetSn= (…(A1+n)A2+n–1)A3+…+2)An+1For givenNprintSNInputOne integerN. 1 ≤N≤ 200OutputLine containingSNSampleinputoutput3((sin(1)+3)sin(1–sin(2))+2)sin(1–sin(2+sin(3)))+1Problem Author:Vladimir GladkovProblem Source:Ural Collegiate Programming Contest, April 20 阅读全文
posted @ 2014-01-15 16:04 acutus 阅读(251) 评论(0) 推荐(0) 编辑
摘要: Consider the sequence of numbersai,i= 0, 1, 2, …, which satisfies the following requirements:a0= 0a1= 1a2i=aia2i+1=ai+ai+1for everyi= 1, 2, 3, … .Write a program which for a given value ofnfinds the largest number among the numbersa0,a1, …,an.InputYou are given several test cases (not more than 10). 阅读全文
posted @ 2014-01-15 14:34 acutus 阅读(305) 评论(0) 推荐(0) 编辑
摘要: Your task is to find the sum of all integer numbers lying between 1 andNinclusive.InputThe input consists of a single integerNthat is not greater than 10000 by it's absolute value.OutputWrite a single integer number that is the sum of all integer numbers lying between 1 andNinclusive.Sampleinput 阅读全文
posted @ 2014-01-14 23:29 acutus 阅读(246) 评论(0) 推荐(0) 编辑
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