Ural 1001 - Reverse Root

The problem is so easy, that the authors were lazy to write a statement for it!

Input

The input stream contains a set of integer numbers A_i (0 ≤ A_i ≤ 10¹⁸). The numbers are separated by any number of spaces and line breaks. A size of the input stream does not exceed 256 KB.

Output

For each number A_i from the last one till the first one you should output its square root. Each square root should be printed in a separate line with at least four digits after decimal point.

Sample

input	output
1427 0 876652098643267843 5276538	2297.0716 936297014.1164 0.0000 37.7757

Problem Author: Prepared by Dmitry Kovalioff

// Ural Problem 1001. Reverse Root
// Verdict: Accepted  
// Submission Date: 22:34:56 12 Jan 2014
// Run Time: 0.328s
//  
// 版权所有（C）acutus。(mail: acutus@126.com) 
//  
// [解题方法]  
// 简单题，直接按题意输入输出即可
// 注意：数组开大点，要使用全局数组

#include<stdio.h>

double a[300000];

void solve(void)
{
    int i;
    double t;
    i = 0;
    while(scanf("%lf",&t) != EOF) a[i++] = t;
    i--;
    while(i >= 0) {
        printf("%.4lf\n", sqrt(a[i]));
        i--;
    }
}

int main(void)
{
    solve();
    return 0;
}