摘要: 题意:n个点m条边,找点集个数,点集满足有任意三个点成环,或者三个点互不相连 题解:暴力复杂度O(n^5/120*O(ok))==O(能过) //#pragma comment(linker, "/stack:200000000") //#pragma GCC optimize("Ofast,no- 阅读全文
posted @ 2018-05-17 20:19 walfy 阅读(236) 评论(0) 推荐(0) 编辑