hdu 1686 Oulipo(裸KMP)

Problem Description

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1
3
0
解题思路:计算模式串在主串中出现的次数。
AC代码:
 1 #include<cstdio>
 2 #include<string.h>
 3 const int maxn=1e4+5;
 4 const int maxm=1e6+5;
 5 char text[maxm],pattern[maxn];
 6 int prefix[maxn],lena,lenb,num,t;
 7 void get_prefix_table(){//处理模式串前缀表
 8     int j=0,pos=-1;
 9     prefix[0]=-1;
10     while(j<lenb){
11         if(pos==-1||pattern[pos]==pattern[j])prefix[++j]=++pos;
12         else pos=prefix[pos];
13     }
14 }
15 void kmp_search(){
16     int i=0,j=0;
17     while(i<lena){
18         if(j==-1||text[i]==pattern[j])i++,j++;
19         else j=prefix[j];
20         if(j==lenb)num++,j=prefix[j];//此时的j应退回到j前面子串的最长公共前后缀长度的位置进行下一次匹配,可以有相交的模式串
21     }
22 }
23 int main(){
24     while(~scanf("%d",&t)){
25         while(t--){
26             scanf("%s%s",pattern,text);
27             memset(prefix,0,sizeof(prefix));
28             num=0,lena=strlen(text),lenb=strlen(pattern);
29             get_prefix_table();
30             kmp_search();
31             printf("%d\n",num);
32         }
33     }
34     return 0;
35 }

 

posted @ 2018-08-10 09:53  霜雪千年  阅读(130)  评论(0编辑  收藏  举报