摘要：
public static void main(String[] args) { System.out.println(f(1000)); }public static double f(double n){ if (n==1){ return 1; }else { return (n*f(n-1) 阅读全文
摘要：
public static void main(String[] args) {printmax(34,3,2,5,67);printmax(new double[]{1,2,3}); } public static void printmax(double...number){ if (numbe 阅读全文