摘要: #抽象:函数"""#1 计算斐波拉契函数fib=[0,1]for i in range(10): fib.append(fib[-2]+fib[-1])print(fib)#2创建函数def fibs(num): '计算前10个斐波拉契数'#文档字符串 result = [0,1] for i in 阅读全文
posted @ 2017-08-04 14:16 喻晓生 阅读(253) 评论(0) 推荐(0) 编辑
摘要: #语句'''#+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++##1 为函数提供别名from math import sqrt as Testprint(Test(4))#2 序列解包x,y,z = 1,23,4pri 阅读全文
posted @ 2017-08-04 10:47 喻晓生 阅读(206) 评论(0) 推荐(0) 编辑