字牌游戏

先来看个扑克牌在代码中的可以的定义

from collections import namedtuple
Card=namedtuple('Card_name',['rank','suit'])
C1=Card(2,'red')
print(C1)#Card_name(rank=2, suit='red')
print(C1.rank)#2

 

再来来纸牌的代码

from collections import namedtuple
Card=namedtuple('Card',['rank','suit'])
class FranchDeck:
    ranks = [str(n) for n in range(2,11)] + list('JQKA')
    suits = ['红心','方板','梅花','黑桃']
    def __init__(self):
        self.__cards = [Card(rank,suit) for rank in FranchDeck.ranks
                                        for suit in FranchDeck.suits]

    def __len__(self):
        return len(self.__cards)#list元素的个数

    def __getitem__(self, item):
        return self.__cards[item]
    def __setitem__(self,key,value):
        self.__cards[key]=value


deck = FranchDeck()
print(len(deck._FranchDeck__cards))print(deck._FranchDeck__cards)print(deck.__dict__)print(deck[0])#调用了__getitem__print(deck[51])#调用了__getitem__
from random import choice
print(choice(deck))
from random import shuffle
shuffle(deck)
print(deck.__dict__)
print(deck[0])
print(deck[9])

 

解析:

choice函数需要用到__len__和__getiem__两个方法

首先调用__len__,方法得到一个返回值——数字,然后0——数字的范围随机去一个数字,然后填入__getitem__的方法中,的到的返回值,便是整的返回值了。如果报错,说明__getitem__

的代码写入有问题,不支持此函数的索引报错代码 '类名' object does not support indexing,即__getitem__不支持此 对象名[数字]这种的索引方式。

shuffle函数需要用用到__len__,__getitem__和__setitem__三个方法

首先调用len方法,拿到返回值,然后在把0到返回的数字带入get中,拿到key和value,只不过key是数字,然后把key和value的对应关系打乱,依次用set方法把key和value带入,便完成了重新

洗牌