uva11584

将课本上所述方法实现即可,代码如下:

/*
 * Author:  Bingo
 * Created Time:  2015/1/25 23:49:49
 * File Name: uva11584.cpp
 */
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <string>
#include <vector>
#include <stack>
#include <queue>
#include <set>
#include <time.h>
using namespace std;
const int maxint = -1u>>1;
const int maxlen=1050;
int d[maxlen];
int s[maxlen][maxlen];
string st;
int work(){
    int len=st.size();
    memset(s,0,sizeof(s));
    for (int i=0;i<len;i++){
        int p,q;
        s[i][i]=1;
        //ji
        p=i-1;q=i+1;
        while (p>=0&&q<len&&st[p]==st[q]){
            s[p][q]=1;
            p--;q++;
        }
        //odd_left
        p=i-1;q=i;
        while (p>=0&&q<len&&st[p]==st[q]){
            s[p][q]=1;
            p--;q++;
        }
        //odd_right
        p=i;q=i+1;
        while (p>=0&&q<len&&st[p]==st[q]){
            s[p][q]=1;
            p--;q++;
        }
    }
}//s[i][j]是否为回文串
int main()
{
    int T;
    cin>>T;
    //string st;
    while (T--){
        cin>>st;
        work();
        int len=st.size();
        for (int i=0;i<len;i++)
            d[i]=100000;
        for (int i=0;i<len;i++){
            int j=0;
            if (s[0][i]) d[i]=1;
            else
            for (j=0;j<i;j++){
                if (s[j+1][i]) d[i]=min(d[i],d[j]+1);
            }
        }
        cout<<d[len-1]<<endl;
    }
    return 0;
}
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posted @ 2015-02-02 12:01  ACBingo  阅读(420)  评论(0编辑  收藏  举报