边工作边刷题:70天一遍leetcode: day 94-2

Maximum Size Subarray Sum Equals k

要点:

  • 为什么slinding window或者local ending at方法不行?要得到exact equals k,而array不是sorted。
  • idea:基本利用了partial sum差得到subarray sum。另外因为要得到maxLen,所以从左到右scan的时候,相同的partial sum只记录最左边的即可(显然如果是minLen,记录最右)。
    • sum_diff中作为减数的partial sum是exclusive的,所以长度公式是不+1的。同时也容易处理边界条件:初始化map为
    • sum_diff只是右边的partial sum减去左边的,差值即为subarray sum,和结果正负无关

错误点:

  • 注意减法的顺序:partial sum-k

https://repl.it/Clxw

class Solution(object):
    def maxSubArrayLen(self, nums, k):
        """
        :type nums: List[int]
        :type k: int
        :rtype: int
        """
        umap = {0:-1}
        psum = 0
        maxLen = 0
        for i in xrange(len(nums)):
            psum+=nums[i]
            if psum-k in umap:
                maxLen = max(maxLen, i-umap[psum-k])
            if psum not in umap:
                umap[psum]=i
        return maxLen

sol = Solution()
assert sol.maxSubArrayLen([-2,-1,2,1], 1)==2, "max length is 2"
posted @ 2016-07-12 20:21  absolute100  阅读(98)  评论(0编辑  收藏  举报