Move Zeroes——Leetcode
Given an array nums
, write a function to move all 0
's to the end of it while maintaining the relative order of the non-zero elements.
For example, given nums = [0, 1, 0, 3, 12]
, after calling your function, nums
should be [1, 3, 12, 0, 0]
.
Note:
- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.
题目大意:给定一个数组,把所有的0放到数组后面,所有的非0元素放到前面,并且保证非0元素顺序不变。
解题思路,从前往后遍历,遇见0则cnt++,遇见非0则往前移cnt个,最后把后cnt个设置为0就可以了。
public void moveZeroes(int[] nums) { if(nums==null||nums.length==0){ return; } int cnt = 0; for(int i=0;i<nums.length;i++){ if(nums[i]==0){ cnt++; }else{ nums[i-cnt]=nums[i]; } } if(cnt>0){ Arrays.fill(nums,nums.length-cnt,nums.length,0); } }