Move Zeroes——Leetcode

Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:

  1. You must do this in-place without making a copy of the array.
  2. Minimize the total number of operations.

题目大意:给定一个数组,把所有的0放到数组后面,所有的非0元素放到前面,并且保证非0元素顺序不变。

解题思路,从前往后遍历,遇见0则cnt++,遇见非0则往前移cnt个,最后把后cnt个设置为0就可以了。

    public void moveZeroes(int[] nums) {
        if(nums==null||nums.length==0){
            return;
        }
        int cnt = 0;
        for(int i=0;i<nums.length;i++){
            if(nums[i]==0){
                cnt++;
            }else{
                nums[i-cnt]=nums[i];
            }
        }
        if(cnt>0){
            Arrays.fill(nums,nums.length-cnt,nums.length,0);
        }
    }

 

posted @ 2015-09-20 17:09  丶Blank  阅读(174)  评论(0编辑  收藏  举报