【POJ 3415】Common Substrings 长度不小于k的公共子串的个数
长度不小于k的公共子串的个数,论文里有题解,卡了一上午,因为sum没开long long!!!
没开long long毁一生again~~~
以后应该早看POJ里的Discuss啊QAQ
#include<cstdio> #include<cstring> #include<iostream> #include<algorithm> using namespace std; const int N = 200003; int t1[N], t2[N], c[N]; void st(int *x, int *y, int *sa, int n, int m) { int i; for(i = 0; i < m; ++i) c[i] = 0; for(i = 0; i < n; ++i) ++c[x[y[i]]]; for(i = 1; i < m; ++i) c[i] += c[i - 1]; for(i = n - 1; i >= 0; --i) sa[--c[x[y[i]]]] = y[i]; } void mkhz(int *a, int *sa, int n, int m) { int *t, *x = t1, *y = t2, i, j, p; for(i = 0; i < n; ++i) x[i] = a[i], y[i] = i; st(x, y, sa, n, m); for(p = 1, j = 1; p < n; j <<= 1, m = p) { for(p = 0, i = n - j; i < n; ++i) y[p++] = i; for(i = 0; i < n; ++i) if (sa[i] >= j) y[p++] = sa[i] - j; st(x, y, sa, n, m); for(t = x, x = y, y = t, p = 1, x[sa[0]] = 0, i = 1; i < n; ++i) x[sa[i]] = y[sa[i]] == y[sa[i - 1]] && y[sa[i] + j] == y[sa[i - 1] + j] ? p - 1 : p++; } } void mkh(int *r, int *sa, int *rank, int *h, int n) { int i, j, k = 0; for(i = 1; i <= n; ++i) rank[sa[i]] = i; for(i = 1; i <= n; h[rank[i++]] = k) for(k ? --k : 0, j = sa[rank[i] - 1]; r[i + k] == r[j + k]; ++k); } char s[N]; int a[N], sa[N], rank[N], h[N], n, k, sta[N], top, tmp, mark[N]; long long sum[N]; int main() { while (scanf("%d", &k), k) { scanf("%s", s + 1); tmp = strlen(s + 1); s[++tmp] = 1; scanf("%s", s + tmp + 1); n = strlen(s + 1); for(int i = 1; i <= n; ++i) a[i] = s[i]; mkhz(a, sa, n + 1, 130); mkh(a, sa, rank, h, n); long long ans = 0; for(int i = 1; i <= n; ++i) { if (h[i] < k) { top = sum[0] = sum[1] = 0; } else { for(int j = top; sta[j] > h[i] - k + 1 && j; --j) { sum[mark[j]] += h[i] - k + 1 - sta[j]; sta[j] = h[i] - k + 1; } sta[++top] = h[i] - k + 1; if (sa[i - 1] < tmp) mark[top] = 0; if (sa[i - 1] > tmp) mark[top] = 1; sum[mark[top]] += h[i] - k + 1; if (sa[i] < tmp) ans += sum[1]; if (sa[i] > tmp) ans += sum[0]; } } printf("%lld\n", ans); } return 0; }
没开long long,毁我青春,耗我钱财,颓我精神==
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