strtol / strtoll / strtoul / strtoull

function

long int strtol (const char* str, char** endptr, int base); —— Convert string to long integer

long long int strtoll (const char* str, char** endptr, int base); —— Convert string to long long integer

unsigned long int strtoul (const char* str, char** endptr, int base); —— Convert string to unsigned long integer

unsigned long long int strtoull (const char* str, char** endptr, int base); —— Convert string to unsigned long long integer

Parses the C-string str interpreting its content as an integral number of the specified base, which is returned as a long int / long long int / unsigned long int / unsigned long long int value. If endptr is not a null pointer, the function also sets the value of endptr to point to the first character after the number.

The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, takes as many characters as possible that are valid following a syntax that depends on the base parameter, and interprets them as a numerical value. Finally, a pointer to the first character following the integer representation in str is stored in the object pointed by endptr.

If the value of base is zero, the syntax expected is similar to that of integer constants, which is formed by a succession of:

An optional sign character (+ or -)
An optional prefix indicating octal or hexadecimal base ("0" or "0x"/"0X" respectively)
A sequence of decimal digits (if no base prefix was specified) or either octal or hexadecimal digits if a specific prefix is present

If the base value is between 2 and 36, the format expected for the integral number is a succession of any of the valid digits and/or letters needed to represent integers of the specified radix (starting from '0' and up to 'z'/'Z' for radix 36). The sequence may optionally be preceded by a sign (either + or -) and, if base is 16, an optional "0x" or "0X" prefix.

If the first sequence of non-whitespace characters in str is not a valid integral number as defined above, or if no such sequence exists because either str is empty or it contains only whitespace characters, no conversion is performed.

For locales other than the "C" locale, additional subject sequence forms may be accepted.

Parameters

str: C-string beginning with the representation of an integral number.
endptr: Reference to an object of type char*, whose value is set by the function to the next character in str after the numerical value.
This parameter can also be a null pointer, in which case it is not used.
base: Numerical base (radix) that determines the valid characters and their interpretation.
If this is 0, the base used is determined by the format in the sequence (see above).

Return Value

On success, the function returns the converted integral number as a long int / long long int / unsigned long int / unsigned long long int value.
If no valid conversion could be performed, a zero value is returned (0L / 0LL / 0UL / 0ULL).
If the value read is out of the range of representable values by a long int / long long int / unsigned long int / unsigned long long int, the function returnsLONG_MAX orLONG_MIN /LLONG_MAX orLLONG_MIN / ULONG_MAX /ULLONG_MAX (defined in<climits>), and errno is set to ERANGE.

examples

 1 /* strtol example */
 2 #include <stdio.h>      /* printf */
 3 #include <stdlib.h>     /* strtol */
 4 
 5 int main ()
 6 {
 7   char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
 8   char * pEnd;
 9   long int li1, li2, li3, li4;
10   li1 = strtol (szNumbers,&pEnd,10);
11   li2 = strtol (pEnd,&pEnd,16);
12   li3 = strtol (pEnd,&pEnd,2);
13   li4 = strtol (pEnd,NULL,0);
14   printf ("The decimal equivalents are: %ld, %ld, %ld and %ld.\n", li1, li2, li3, li4);
15   return 0;
16 }

运行结果：

The decimal equivalents are: 2001, 6340800, -3624224 and 7340031

 1 /* strtoll example */
 2 #include <stdio.h>      /* printf, NULL */
 3 #include <stdlib.h>     /* strtoll */
 4 
 5 int main ()
 6 {
 7   char szNumbers[] = "1856892505 17b00a12b -01100011010110000010001101100 0x6fffff";
 8   char* pEnd;
 9   long long int lli1, lli2, lli3, lli4;
10   lli1 = strtoll (szNumbers, &pEnd, 10);
11   lli2 = strtoll (pEnd, &pEnd, 16);
12   lli3 = strtoll (pEnd, &pEnd, 2);
13   lli4 = strtoll (pEnd, NULL, 0);
14   printf ("The decimal equivalents are: %lld, %lld, %lld and %lld.\n", lli1, lli2, lli3, lli4);
15   return 0;
16 }

运行结果：

The decimal equivalents are: 1856892505, 6358606123, -208340076 and 7340031

 1 /* strtoul example */
 2 #include <stdio.h>      /* printf, NULL */
 3 #include <stdlib.h>     /* strtoul */
 4 
 5 int main ()
 6 {
 7   char buffer [256];
 8   unsigned long ul;
 9   printf ("Enter an unsigned number: ");
10   fgets (buffer, 256, stdin);
11   ul = strtoul (buffer, NULL, 0);
12   printf ("Value entered: %lu. Its double: %lu\n",ul,ul*2);
13   return 0;
14 }

运行结果：

Enter an unsigned number: 30003
Value entered: 30003. Its double: 60006

 1 /* strtoull example */
 2 #include <stdio.h>      /* printf, NULL */
 3 #include <stdlib.h>     /* strtoull */
 4 
 5 int main ()
 6 {
 7   char szNumbers[] = "250068492 7b06af00 1100011011110101010001100000 0x6fffff";
 8   char * pEnd;
 9   unsigned long long int ulli1, ulli2, ulli3, ulli4;
10   ulli1 = strtoull (szNumbers, &pEnd, 10);
11   ulli2 = strtoull (pEnd, &pEnd, 16);
12   ulli3 = strtoull (pEnd, &pEnd, 2);
13   ulli4 = strtoull (pEnd, NULL, 0);
14   printf ("The decimal equivalents are: %llu, %llu, %llu and %llu.\n", ulli1, ulli2, ulli3, ulli4);
15   return 0;
16 }

运行结果：

The decimal equivalents are: 250068492, 2064035584, 208622688 and 7340031.

封装

  1     bool stringToI32(const std::string &str, int32_t  &val)  
  2     {  
  3         long temp_val = 0;  
  4         bool isOK = stringToL(str, temp_val);  
  5         val = temp_val;  
  6         return isOK && (temp_val >= -0x7fffffff && temp_val <= 0x7fffffff/*32bit整形的有效范围*/);  
  7     }  
  8       
  9     bool stringToU32(const std::string &str, uint32_t  &val)  
 10     {  
 11         unsigned long temp_val = 0;  
 12         bool isOK = stringToUL(str, temp_val);  
 13         val = temp_val;  
 14         return isOK && (temp_val <= 0xffffffff/*32bit无符号整形的有效范围*/);  
 15     }  
 16       
 17     bool stringToI64(const std::string &str, int64_t  &val)  
 18     {  
 19         long long temp_val = 0;  
 20         bool isOK = stringToLL(str, temp_val);  
 21         val = temp_val;  
 22         return isOK && (temp_val >= -0x7fffffffffffffff && temp_val <= 0x7fffffffffffffff/*64bit整形的有效范围*/);  
 23     }  
 24       
 25     bool stringToU64(const std::string &str, uint64_t  &val)  
 26     {  
 27         unsigned long long temp_val = 0;  
 28         bool isOK = stringToULL(str, temp_val);  
 29         val = temp_val;  
 30         return isOK && (temp_val <= 0xffffffffffffffff/*64bit无符号整形的有效范围*/);  
 31     }  
 32       
 33     bool stringToL(const std::string &str, long  &val)  
 34     {  
 35         bool isOK = false;  
 36         const char *nptr = str.c_str();  
 37         char *endptr = NULL;  
 38         errno = 0;  
 39         val = strtol(nptr, &endptr, 10);  
 40         //error ocur  
 41         if ((errno == ERANGE && (val == LONG_MAX || val == LONG_MIN))  
 42             || (errno != 0 && val == 0))  
 43         {  
 44       
 45         }  
 46         //no digit find  
 47         else if (endptr == nptr)  
 48         {  
 49       
 50         }  
 51         else if (*endptr != '\0')  
 52         {  
 53             // printf("Further characters after number: %s\n", endptr);  
 54         }  
 55         else  
 56         {  
 57             isOK = true;  
 58         }  
 59       
 60         return isOK;  
 61     }  
 62       
 63     bool stringToLL(const std::string &str, long long &val)  
 64     {  
 65         bool isOK = false;  
 66         const char *nptr = str.c_str();  
 67         char *endptr = NULL;  
 68         errno = 0;  
 69         val = strtoll(nptr, &endptr, 10);  
 70         //error ocur  
 71         if ((errno == ERANGE && (val == LLONG_MAX || val == LLONG_MIN))  
 72             || (errno != 0 && val == 0))  
 73         {  
 74       
 75         }  
 76         //no digit find  
 77         else if (endptr == nptr)  
 78         {  
 79       
 80         }  
 81         else if (*endptr != '\0')  
 82         {  
 83             // printf("Further characters after number: %s\n", endptr);  
 84         }  
 85         else  
 86         {  
 87             isOK = true;  
 88         }  
 89       
 90         return isOK;  
 91     }  
 92       
 93     bool stringToUL(const std::string &str, unsigned long  &val)  
 94     {  
 95         bool isOK = false;  
 96         const char *nptr = str.c_str();  
 97         char *endptr = NULL;  
 98         errno = 0;  
 99         val = strtoul(nptr, &endptr, 10);  
100         //error ocur  
101         if ((errno == ERANGE && (val == ULONG_MAX))  
102             || (errno != 0 && val == 0))  
103         {  
104       
105         }  
106         //no digit find  
107         else if (endptr == nptr)  
108         {  
109       
110         }  
111         else if (*endptr != '\0')  
112         {  
113             // printf("Further characters after number: %s\n", endptr);  
114         }  
115         else  
116         {  
117             isOK = true;  
118         }  
119       
120         return isOK;  
121     }  
122       
123     bool stringToULL(const std::string &str, unsigned long long &val)  
124     {  
125         bool isOK = false;  
126         const char *nptr = str.c_str();  
127         char *endptr = NULL;  
128         errno = 0;  
129         val = strtoull(nptr, &endptr, 10);  
130         //error ocur  
131         if ((errno == ERANGE && (val == ULLONG_MAX))  
132             || (errno != 0 && val == 0))  
133         {  
134       
135         }  
136         //no digit find  
137         else if (endptr == nptr)  
138         {  
139       
140         }  
141         else if (*endptr != '\0')  
142         {  
143             // printf("Further characters after number: %s\n", endptr);  
144         }  
145         else  
146         {  
147             isOK = true;  
148         }  
149       
150         return isOK;  
151     }

本文参考自：

http://www.cplusplus.com/reference/cstdlib/strtol/

http://www.cplusplus.com/reference/cstdlib/strtoll/

http://www.cplusplus.com/reference/cstdlib/strtoul/

http://www.cplusplus.com/reference/cstdlib/strtoull/

http://blog.csdn.net/ywy2090/article/details/64918801

posted on 2017-11-28 22:15 LastBattle 阅读(1091) 评论(0) 编辑收藏举报

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strtol / strtoll / strtoul / strtoull