HttpWebRequest

            var request = (HttpWebRequest)HttpWebRequest.Create(Config.GoodLineUrlAjax);    // 创建请求
            var respone = (HttpWebResponse)request.GetResponse();                           // 创建响应,发送请求
            var stream = respone.GetResponseStream();
            var streamReader = new StreamReader(stream);
            return streamReader.ReadToEnd();

 

posted @ 2018-06-14 10:27  江境纣州  阅读(11)  评论(0编辑  收藏  举报